Odpowiedź:
zad.1
a,b,c - długości boków trójkąta , Obw= a + b + c
a=6 1/4 dm
b= a + 1 2/5=6 1/4 + 1 2/5= 6 5/20 + 1 8/20 = 7 13/20 dm
c= b + 3/4 = 7 13/20 + 3/4 = 7 13/20 + 15/20 = 7 28/20= 8 8/20=8 2/5 dm
c - a = 8 2/5 - 6 1/4 = 8 8/20 - 6 5/20 = 2 3/20 odp. A
a+b+c= 6 5/20 + 7 13/20 + 8 8/20= 21 26/20= 22 6/20= 22 3/10 odp. C
zad. 2
A. 4 1/5 + 2 2/3=4 3/15 + 2 10/15 = 6 13/15
B. 5 2/9 - 3 5/6 = 5 4/18 - 3 15/18= 1 7/18
C. 4 1/5 - 2 2/3 = 4 3/15 - 2 10/15 = 1 8/15
D. 3 5/6 + 5 2/9 = 3 15/18 + 5 4/18 = 9 1/18
3 5/6 + a = 5 2/9
a = 5 2/9 - 3 5/6 odp. B
b - 4 1/5 = 2 2/3
b = 2 2/3 + 4 1/5 odp. A
4 1/5 - c = 2 2/3
c = 4 1/5 - 2 2/3 odp. C
