Odpowiedź :
[tex]dane:\\r = 10 \ m\\T = 2 \ s\\szukane:\\v = ?\\\\Rozwiazanie\\\\v = \frac{2\pi r}{T}\\\\v = \frac{2\cdot3,14\cdot10 \ m}{2 \ s} = 31,4\frac{m}{s}[/tex]
[tex]dane:\\r = 10 \ m\\T = 2 \ s\\szukane:\\v = ?\\\\Rozwiazanie\\\\v = \frac{2\pi r}{T}\\\\v = \frac{2\cdot3,14\cdot10 \ m}{2 \ s} = 31,4\frac{m}{s}[/tex]