Odpowiedź :
[tex]dane:\\p = 200 \ Pa = 200 \ \frac{N}{m^{2}}\\S = 1 \ m^{2}\\szukane:\\F = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ |\cdot S\\\\F = p\cdot S\\\\F = 200\frac{N}{m^{2}}\cdot1 \ m^{2}}\\\\F = 200 \ N[/tex]
[tex]dane:\\p = 200 \ Pa = 200 \ \frac{N}{m^{2}}\\S = 1 \ m^{2}\\szukane:\\F = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ |\cdot S\\\\F = p\cdot S\\\\F = 200\frac{N}{m^{2}}\cdot1 \ m^{2}}\\\\F = 200 \ N[/tex]