[tex]dane:\\m = 72 \ kg\\S = 560 \ cm^{2} = 0,056 \ m^{2}\\g = 10\frac{N}{kg}\\szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\F= m\cdot g = 72 \ kg\cdot10\frac{N}{kg} = 720 \ N\\\\p = \frac{720 \ N}{0,056 \ m^{2}}\\\\p \approx12 \ 857 \ Pa[/tex]
